1 | #region License Information
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2 | /* HeuristicLab
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3 | * Copyright (C) 2002-2018 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
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4 | *
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5 | * This file is part of HeuristicLab.
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6 | *
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7 | * HeuristicLab is free software: you can redistribute it and/or modify
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8 | * it under the terms of the GNU General Public License as published by
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9 | * the Free Software Foundation, either version 3 of the License, or
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10 | * (at your option) any later version.
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11 | *
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12 | * HeuristicLab is distributed in the hope that it will be useful,
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13 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
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14 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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15 | * GNU General Public License for more details.
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16 | *
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17 | * You should have received a copy of the GNU General Public License
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18 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
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19 | */
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20 | #endregion
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21 | using System;
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22 | using System.Collections.Generic;
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23 | using System.Linq;
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24 |
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25 | namespace HeuristicLab.Problems.TestFunctions.MultiObjective {
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26 |
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27 | /// <summary>
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28 | /// The generational Distance is defined as the pth-root of the sum of all d[i]^(p) divided by the size of the front
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29 | /// where d[i] is the minimal distance the ith point of the evaluated front has to any point in the optimal pareto front.
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30 | /// p is a dampening factor and is normally set to 1.
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31 | /// http://shodhganga.inflibnet.ac.in/bitstream/10603/15070/28/28_appendix_h.pdf
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32 | /// </summary>
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33 | public static class GenerationalDistance {
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34 |
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35 | public static double Calculate(IEnumerable<double[]> front, IEnumerable<double[]> optimalFront, double p) {
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36 | if (front == null || optimalFront == null) throw new ArgumentNullException("Fronts must not be null.");
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37 | if (!front.Any()) throw new ArgumentException("Front must not be empty.");
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38 | if (p == 0.0) throw new ArgumentException("p must not be 0.0.");
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39 |
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40 |
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41 | double sum = front.Select(r => Math.Pow(Utilities.MinimumDistance(r, optimalFront), p)).Sum();
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42 | return Math.Pow(sum, 1 / p) / front.Count();
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43 | }
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44 |
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45 | }
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46 | }
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