1 | #region License Information
|
---|
2 |
|
---|
3 | /* HeuristicLab
|
---|
4 | * Copyright (C) Heuristic and Evolutionary Algorithms Laboratory (HEAL)
|
---|
5 | *
|
---|
6 | * This file is part of HeuristicLab.
|
---|
7 | *
|
---|
8 | * HeuristicLab is free software: you can redistribute it and/or modify
|
---|
9 | * it under the terms of the GNU General Public License as published by
|
---|
10 | * the Free Software Foundation, either version 3 of the License, or
|
---|
11 | * (at your option) any later version.
|
---|
12 | *
|
---|
13 | * HeuristicLab is distributed in the hope that it will be useful,
|
---|
14 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
|
---|
15 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
|
---|
16 | * GNU General Public License for more details.
|
---|
17 | *
|
---|
18 | * You should have received a copy of the GNU General Public License
|
---|
19 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
|
---|
20 | */
|
---|
21 |
|
---|
22 | #endregion
|
---|
23 |
|
---|
24 | using System;
|
---|
25 | using System.Collections.Generic;
|
---|
26 | using System.Linq;
|
---|
27 | using HeuristicLab.Encodings.SymbolicExpressionTreeEncoding;
|
---|
28 | //using HeuristicLab.EvolutionTracking;
|
---|
29 |
|
---|
30 | namespace HeuristicLab.Problems.DataAnalysis.Symbolic {
|
---|
31 | public static class SymbolicExpressionTreeMatching {
|
---|
32 | public static bool ContainsSubtree(this ISymbolicExpressionTreeNode root, ISymbolicExpressionTreeNode subtree, SymbolicExpressionTreeNodeEqualityComparer comparer) {
|
---|
33 | return FindMatches(root, subtree, comparer).Any();
|
---|
34 | }
|
---|
35 | public static IEnumerable<ISymbolicExpressionTreeNode> FindMatches(ISymbolicExpressionTree tree, ISymbolicExpressionTreeNode subtree, SymbolicExpressionTreeNodeEqualityComparer comparer) {
|
---|
36 | return FindMatches(tree.Root, subtree, comparer);
|
---|
37 | }
|
---|
38 |
|
---|
39 | public static IEnumerable<ISymbolicExpressionTreeNode> FindMatches(ISymbolicExpressionTreeNode root, ISymbolicExpressionTreeNode subtree, SymbolicExpressionTreeNodeEqualityComparer comp) {
|
---|
40 | var fragmentLength = subtree.GetLength();
|
---|
41 | // below, we use ">=" for Match(n, subtree, comp) >= fragmentLength because in case of relaxed conditions,
|
---|
42 | // we can have multiple matches of the same node
|
---|
43 |
|
---|
44 | return root.IterateNodesBreadth().Where(n => n.GetLength() >= fragmentLength && Match(n, subtree, comp) == fragmentLength);
|
---|
45 | }
|
---|
46 |
|
---|
47 | ///<summary>
|
---|
48 | /// Finds the longest common subsequence in quadratic time and linear space
|
---|
49 | /// Variant of:
|
---|
50 | /// D. S. Hirschberg. A linear space algorithm for or computing maximal common subsequences. 1975.
|
---|
51 | /// http://dl.acm.org/citation.cfm?id=360861
|
---|
52 | /// </summary>
|
---|
53 | /// <returns>Number of pairs that were matched</returns>
|
---|
54 | public static int Match(ISymbolicExpressionTreeNode a, ISymbolicExpressionTreeNode b, ISymbolicExpressionTreeNodeSimilarityComparer comp) {
|
---|
55 | if (!comp.Equals(a, b)) return 0;
|
---|
56 | int m = a.SubtreeCount;
|
---|
57 | int n = b.SubtreeCount;
|
---|
58 | if (m == 0 || n == 0) return 1;
|
---|
59 | var matrix = new int[m + 1, n + 1];
|
---|
60 | for (int i = 1; i <= m; ++i) {
|
---|
61 | var ai = a.GetSubtree(i - 1);
|
---|
62 | for (int j = 1; j <= n; ++j) {
|
---|
63 | var bj = b.GetSubtree(j - 1);
|
---|
64 | int match = Match(ai, bj, comp);
|
---|
65 | matrix[i, j] = Math.Max(Math.Max(matrix[i, j - 1], matrix[i - 1, j]), matrix[i - 1, j - 1] + match);
|
---|
66 | }
|
---|
67 | }
|
---|
68 | return matrix[m, n] + 1;
|
---|
69 | }
|
---|
70 |
|
---|
71 | /// <summary>
|
---|
72 | /// Calculates the difference between two symbolic expression trees.
|
---|
73 | /// </summary>
|
---|
74 | /// <param name="tree">The first symbolic expression tree</param>
|
---|
75 | /// <param name="other">The second symbolic expression tree</param>
|
---|
76 | /// <returns>Returns the root of the subtree (from T1) by which T1 differs from T2, or null if no difference is found.</returns>
|
---|
77 | public static ISymbolicExpressionTreeNode Difference(this ISymbolicExpressionTree tree, ISymbolicExpressionTree other) {
|
---|
78 | return Difference(tree.Root, other.Root);
|
---|
79 | }
|
---|
80 |
|
---|
81 | public static ISymbolicExpressionTreeNode Difference(this ISymbolicExpressionTreeNode node, ISymbolicExpressionTreeNode other) {
|
---|
82 | var a = node.IterateNodesPrefix().ToList();
|
---|
83 | var b = other.IterateNodesPrefix().ToList();
|
---|
84 | var list = new List<ISymbolicExpressionTreeNode>();
|
---|
85 | for (int i = 0, j = 0; i < a.Count && j < b.Count; ++i, ++j) {
|
---|
86 | var s1 = a[i].ToString();
|
---|
87 | var s2 = b[j].ToString();
|
---|
88 | if (s1 == s2) continue;
|
---|
89 | list.Add(a[i]);
|
---|
90 | // skip subtrees since the parents are already different
|
---|
91 | i += a[i].SubtreeCount;
|
---|
92 | j += b[j].SubtreeCount;
|
---|
93 | }
|
---|
94 | ISymbolicExpressionTreeNode result = list.Count > 0 ? LowestCommonAncestor(node, list) : null;
|
---|
95 | return result;
|
---|
96 | }
|
---|
97 |
|
---|
98 | private static ISymbolicExpressionTreeNode LowestCommonAncestor(ISymbolicExpressionTreeNode root, List<ISymbolicExpressionTreeNode> nodes) {
|
---|
99 | if (nodes.Count == 0)
|
---|
100 | throw new ArgumentException("The nodes list should contain at least one element.");
|
---|
101 |
|
---|
102 | if (nodes.Count == 1)
|
---|
103 | return nodes[0];
|
---|
104 |
|
---|
105 | int minLevel = nodes.Min(x => root.GetBranchLevel(x));
|
---|
106 |
|
---|
107 | // bring the nodes in the nodes to the same level (relative to the root)
|
---|
108 | for (int i = 0; i < nodes.Count; ++i) {
|
---|
109 | var node = nodes[i];
|
---|
110 | var level = root.GetBranchLevel(node);
|
---|
111 | for (int j = minLevel; j < level; ++j)
|
---|
112 | node = node.Parent;
|
---|
113 | nodes[i] = node;
|
---|
114 | }
|
---|
115 |
|
---|
116 | // while not all the elements in the nodes are equal, go one level up
|
---|
117 | while (nodes.Any(x => x != nodes[0])) {
|
---|
118 | for (int i = 0; i < nodes.Count; ++i)
|
---|
119 | nodes[i] = nodes[i].Parent;
|
---|
120 | }
|
---|
121 |
|
---|
122 | return nodes[0];
|
---|
123 | }
|
---|
124 | }
|
---|
125 | }
|
---|