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source: stable/HeuristicLab.Analysis/3.3/Statistics/EnumerableStatisticsExtension.cs @ 17456

Last change on this file since 17456 was 17181, checked in by swagner, 5 years ago

#2875: Merged r17180 from trunk to stable

File size: 1.7 KB
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[9998]1#region License Information
2/* HeuristicLab
[17181]3 * Copyright (C) Heuristic and Evolutionary Algorithms Laboratory (HEAL)
[9998]4 *
5 * This file is part of HeuristicLab.
6 *
7 * HeuristicLab is free software: you can redistribute it and/or modify
8 * it under the terms of the GNU General Public License as published by
9 * the Free Software Foundation, either version 3 of the License, or
10 * (at your option) any later version.
11 *
12 * HeuristicLab is distributed in the hope that it will be useful,
13 * but WITHOUT ANY WARRANTY; without even the implied warranty of
14 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
15 * GNU General Public License for more details.
16 *
17 * You should have received a copy of the GNU General Public License
18 * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
19 */
20#endregion
21
22using System;
23using System.Collections.Generic;
24using System.Linq;
25using HeuristicLab.Common;
26
27namespace HeuristicLab.Analysis.Statistics {
28  public static class EnumerableStatisticExtensions {
29    public static Tuple<double, double> ConfidenceIntervals(this IEnumerable<double> values, double alpha) {
[11919]30      return ConfidenceIntervals(values.ToArray(), alpha);
31    }
[10017]32
[11919]33    public static Tuple<double, double> ConfidenceIntervals(this double[] values, double alpha) {
[9998]34      double lower, upper;
[11919]35      int n = values.Length;
36      if (n <= 1) return new Tuple<double, double>(double.NaN, double.NaN);
37
[9998]38      double s = values.StandardDeviation();
39      double x = values.Average();
[11699]40      double t = alglib.invstudenttdistribution(n - 1, (1.0 - alpha) / 2.0);
[9998]41
[11699]42      lower = x + t * (s / Math.Sqrt(n));
43      upper = x - t * (s / Math.Sqrt(n));
[9998]44
45      return new Tuple<double, double>(lower, upper);
46    }
47  }
48}
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