1 | #region License Information
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2 | /* HeuristicLab
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3 | * Copyright (C) 2002-2011 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
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4 | *
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5 | * This file is part of HeuristicLab.
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6 | *
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7 | * HeuristicLab is free software: you can redistribute it and/or modify
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8 | * it under the terms of the GNU General Public License as published by
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9 | * the Free Software Foundation, either version 3 of the License, or
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10 | * (at your option) any later version.
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11 | *
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12 | * HeuristicLab is distributed in the hope that it will be useful,
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13 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
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14 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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15 | * GNU General Public License for more details.
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16 | *
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17 | * You should have received a copy of the GNU General Public License
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18 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
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19 | */
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20 | #endregion
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21 |
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22 | using System;
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23 | using System.Globalization;
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24 | using HeuristicLab.Data;
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25 | using Microsoft.VisualStudio.TestTools.UnitTesting;
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26 |
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27 | namespace HeuristicLab.Analysis.Tests {
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28 | [TestClass]
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29 | public class MultidimensionalScalingTest {
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30 | [TestMethod]
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31 | public void TestGoodnessOfFit() {
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32 | double stress;
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33 | DoubleMatrix distances3 = new DoubleMatrix(3, 3);
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34 | // Example 1: A right triangle
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35 | distances3[0, 1] = distances3[1, 0] = 3;
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36 | distances3[0, 2] = distances3[2, 0] = 4;
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37 | distances3[1, 2] = distances3[2, 1] = 5;
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38 | stress = MultidimensionalScaling.CalculateNormalizedStress(distances3,
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39 | MultidimensionalScaling.KruskalShepard(distances3));
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40 | Assert.IsTrue(stress < 0.1);
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41 | // Example 2: An arbitrary triangle
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42 | distances3[0, 1] = distances3[1, 0] = 8;
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43 | distances3[0, 2] = distances3[2, 0] = 6.4;
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44 | distances3[1, 2] = distances3[2, 1] = 5;
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45 | DoubleMatrix coords3 = MultidimensionalScaling.KruskalShepard(distances3);
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46 | Console.WriteLine("Coordinates: ");
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47 | Console.WriteLine("A = ({0}, {1}), B = ({2}, {3}), C = ({4}, {5})", coords3[0, 0], coords3[0, 1], coords3[1, 0], coords3[1, 1], coords3[2, 0], coords3[2, 1]);
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48 | stress = MultidimensionalScaling.CalculateNormalizedStress(distances3, coords3);
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49 | Console.WriteLine("Stress = " + stress.ToString(CultureInfo.InvariantCulture.NumberFormat));
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50 | Assert.IsTrue(stress < 0.1);
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51 | DoubleMatrix distances4 = new DoubleMatrix(4, 4);
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52 | // Example 3: A small square
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53 | distances4[0, 1] = distances4[1, 0] = 1;
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54 | distances4[0, 2] = distances4[2, 0] = Math.Sqrt(2);
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55 | distances4[0, 3] = distances4[3, 0] = 1;
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56 | distances4[1, 2] = distances4[2, 1] = 1;
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57 | distances4[1, 3] = distances4[3, 1] = Math.Sqrt(2);
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58 | distances4[2, 3] = distances4[3, 2] = 1;
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59 | stress = MultidimensionalScaling.CalculateNormalizedStress(distances4,
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60 | MultidimensionalScaling.KruskalShepard(distances4));
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61 | Assert.IsTrue(stress < 0.1);
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62 | // Example 4: A large square
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63 | distances4[0, 1] = distances4[1, 0] = 1000;
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64 | distances4[0, 2] = distances4[2, 0] = Math.Sqrt(2000000);
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65 | distances4[0, 3] = distances4[3, 0] = 1000;
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66 | distances4[1, 2] = distances4[2, 1] = 1000;
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67 | distances4[1, 3] = distances4[3, 1] = Math.Sqrt(2000000);
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68 | distances4[2, 3] = distances4[3, 2] = 1000;
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69 | stress = MultidimensionalScaling.CalculateNormalizedStress(distances4,
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70 | MultidimensionalScaling.KruskalShepard(distances4));
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71 | Assert.IsTrue(stress < 0.1);
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72 | // Example 5: An arbitrary cloud of 8 points in a plane
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73 | DoubleMatrix distancesK = GetDistances(new double[,] { { 2, 1 }, { 5, 2 }, { 7, 1 }, { 4, 0 }, { 3, 3 }, { 4, 2 }, { 1, 8 }, { 6, 3 } });
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74 | stress = MultidimensionalScaling.CalculateNormalizedStress(distancesK,
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75 | MultidimensionalScaling.KruskalShepard(distancesK));
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76 | Assert.IsTrue(stress < 0.1);
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77 | // Example 6: A tetrahedron
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78 | distancesK = GetDistances(new double[,] { { 0, 0, 0 }, { 4, 0, 0 }, { 2, 3.4641, 0 }, { 2, 1.1547, 3.2660 } });
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79 | stress = MultidimensionalScaling.CalculateNormalizedStress(distancesK,
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80 | MultidimensionalScaling.KruskalShepard(distancesK));
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81 | Assert.IsTrue(stress < 0.1);
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82 | // Example 7: A matrix of perceived dissimilarities between 14 colors, published in the literature
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83 | distancesK = new DoubleMatrix(new double[,] {
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84 | { 0.00, 0.14, 0.58, 0.58, 0.82, 0.94, 0.93, 0.96, 0.98, 0.93, 0.91, 0.88, 0.87, 0.84 },
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85 | { 0.14, 0.00, 0.50, 0.56, 0.78, 0.91, 0.93, 0.93, 0.98, 0.96, 0.93, 0.89, 0.87, 0.86 },
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86 | { 0.58, 0.50, 0.00, 0.19, 0.53, 0.83, 0.90, 0.92, 0.98, 0.99, 0.98, 0.99, 0.95, 0.97 },
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87 | { 0.58, 0.56, 0.19, 0.00, 0.46, 0.75, 0.90, 0.91, 0.98, 0.99, 1.00, 0.99, 0.98, 0.96 },
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88 | { 0.82, 0.78, 0.53, 0.46, 0.00, 0.39, 0.69, 0.74, 0.93, 0.98, 0.98, 0.99, 0.98, 1.00 },
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89 | { 0.94, 0.91, 0.83, 0.75, 0.39, 0.00, 0.38, 0.55, 0.86, 0.92, 0.98, 0.98, 0.98, 0.99 },
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90 | { 0.93, 0.93, 0.90, 0.90, 0.69, 0.38, 0.00, 0.27, 0.78, 0.86, 0.95, 0.98, 0.98, 1.00 },
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91 | { 0.96, 0.93, 0.92, 0.91, 0.74, 0.55, 0.27, 0.00, 0.67, 0.81, 0.96, 0.97, 0.98, 0.98 },
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92 | { 0.98, 0.98, 0.98, 0.98, 0.93, 0.86, 0.78, 0.67, 0.00, 0.42, 0.63, 0.73, 0.80, 0.77 },
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93 | { 0.93, 0.96, 0.99, 0.99, 0.98, 0.92, 0.86, 0.81, 0.42, 0.00, 0.26, 0.50, 0.59, 0.72 },
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94 | { 0.91, 0.93, 0.98, 1.00, 0.98, 0.98, 0.95, 0.96, 0.63, 0.26, 0.00, 0.24, 0.38, 0.45 },
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95 | { 0.88, 0.89, 0.99, 0.99, 0.99, 0.98, 0.98, 0.97, 0.73, 0.50, 0.24, 0.00, 0.15, 0.32 },
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96 | { 0.87, 0.87, 0.95, 0.98, 0.98, 0.98, 0.98, 0.98, 0.80, 0.59, 0.38, 0.15, 0.00, 0.24 },
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97 | { 0.84, 0.86, 0.97, 0.96, 1.00, 0.99, 1.00, 0.98, 0.77, 0.72, 0.45, 0.32, 0.24, 0.00 }});
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98 | stress = MultidimensionalScaling.CalculateNormalizedStress(distancesK,
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99 | MultidimensionalScaling.KruskalShepard(distancesK));
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100 | Assert.IsTrue(stress < 0.1);
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101 | }
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102 |
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103 | internal DoubleMatrix GetDistances(double[,] coordinates) {
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104 | int dimension = coordinates.GetLength(0);
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105 | DoubleMatrix distances = new DoubleMatrix(dimension, dimension);
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106 | for (int i = 0; i < dimension - 1; i++)
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107 | for (int j = i + 1; j < dimension; j++) {
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108 | double sum = 0;
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109 | for (int k = 0; k < coordinates.GetLength(1); k++)
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110 | sum += (coordinates[i, k] - coordinates[j, k]) * (coordinates[i, k] - coordinates[j, k]);
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111 | distances[i, j] = distances[j, i] = Math.Sqrt(sum);
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112 | }
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113 | return distances;
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114 | }
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115 | }
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116 | }
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