[7849] | 1 | #region License Information
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| 2 | /* HeuristicLab
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| 3 | * Copyright (C) 2002-2012 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
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| 4 | *
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| 5 | * This file is part of HeuristicLab.
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| 6 | *
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| 7 | * HeuristicLab is free software: you can redistribute it and/or modify
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| 8 | * it under the terms of the GNU General Public License as published by
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| 9 | * the Free Software Foundation, either version 3 of the License, or
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| 10 | * (at your option) any later version.
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| 11 | *
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| 12 | * HeuristicLab is distributed in the hope that it will be useful,
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| 13 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
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| 14 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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| 15 | * GNU General Public License for more details.
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| 16 | *
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| 17 | * You should have received a copy of the GNU General Public License
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| 18 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
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| 19 | */
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| 20 | #endregion
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| 21 |
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| 22 | using System;
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| 23 | using System.Collections.Generic;
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| 24 | using System.Linq;
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| 25 | using HeuristicLab.Random;
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| 26 |
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| 27 | namespace HeuristicLab.Problems.Instances.DataAnalysis {
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| 28 | public static class ValueGenerator {
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| 29 | private static FastRandom rand = new FastRandom();
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| 30 |
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[8660] | 31 | /// <summary>
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| 32 | /// Generates a sequence of evenly spaced points between start and end (inclusive!).
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| 33 | /// </summary>
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| 34 | /// <param name="start">The smallest and first value of the sequence.</param>
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| 35 | /// <param name="end">The largest and last value of the sequence.</param>
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| 36 | /// <param name="stepWidth">The step size between subsequent values.</param>
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| 37 | /// <returns>An sequence of values from start to end (inclusive)</returns>
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[7849] | 38 | public static IEnumerable<double> GenerateSteps(double start, double end, double stepWidth) {
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[8660] | 39 | if (start > end) throw new ArgumentException("start must be less than or equal end.");
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| 40 | if (stepWidth <= 0) throw new ArgumentException("stepwith must be larger than zero.", "stepWidth");
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| 41 | double x = start;
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| 42 | while (x <= end) {
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| 43 | yield return x;
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| 44 | x += stepWidth;
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| 45 | }
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[7849] | 46 | }
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| 47 |
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[8660] | 48 | /// <summary>
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| 49 | /// Generates uniformly distributed values between start and end (inclusive!)
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| 50 | /// </summary>
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| 51 | /// <param name="n">Number of values to generate.</param>
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| 52 | /// <param name="start">The lower value (inclusive)</param>
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| 53 | /// <param name="end">The upper value (inclusive)</param>
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| 54 | /// <returns>An enumerable including n values in [start, end]</returns>
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| 55 | public static IEnumerable<double> GenerateUniformDistributedValues(int n, double start, double end) {
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| 56 | for (int i = 0; i < n; i++) {
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| 57 | // we need to return a random value including end.
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| 58 | // so we cannot use rand.NextDouble() as it returns a value strictly smaller than 1.
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| 59 | double r = rand.NextUInt() / (double)uint.MaxValue; // r \in [0,1]
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| 60 | yield return r * (end - start) + start;
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| 61 | }
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[7849] | 62 | }
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| 63 |
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[8660] | 64 | /// <summary>
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| 65 | /// Generates normally distributed values sampling from N(mu, sigma)
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| 66 | /// </summary>
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| 67 | /// <param name="n">Number of values to generate.</param>
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| 68 | /// <param name="mu">The mu parameter of the normal distribution</param>
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| 69 | /// <param name="sigma">The sigma parameter of the normal distribution</param>
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| 70 | /// <returns>An enumerable including n values ~ N(mu, sigma)</returns>
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| 71 | public static IEnumerable<double> GenerateNormalDistributedValues(int n, double mu, double sigma) {
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| 72 | for (int i = 0; i < n; i++)
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[7849] | 73 | yield return NormalDistributedRandom.NextDouble(rand, mu, sigma);
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| 74 | }
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| 75 |
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| 76 | // iterative approach
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| 77 | public static IEnumerable<IEnumerable<double>> GenerateAllCombinationsOfValuesInLists(List<List<double>> lists) {
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| 78 | List<List<double>> allCombinations = new List<List<double>>();
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| 79 | if (lists.Count < 1) {
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| 80 | return allCombinations;
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| 81 | }
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| 82 |
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| 83 | List<IEnumerator<double>> enumerators = new List<IEnumerator<double>>();
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| 84 | foreach (var list in lists) {
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| 85 | allCombinations.Add(new List<double>());
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| 86 | enumerators.Add(list.GetEnumerator());
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| 87 | }
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| 88 |
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| 89 | bool finished = !enumerators.All(x => x.MoveNext());
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| 90 |
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| 91 | while (!finished) {
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| 92 | GetCurrentCombination(enumerators, allCombinations);
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| 93 | finished = MoveNext(enumerators, lists);
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| 94 | }
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| 95 | return allCombinations;
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| 96 | }
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| 97 |
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| 98 | private static bool MoveNext(List<IEnumerator<double>> enumerators, List<List<double>> lists) {
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| 99 | int cur = enumerators.Count - 1;
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| 100 | while (cur >= 0 && !enumerators[cur].MoveNext()) {
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| 101 | enumerators[cur] = lists[cur].GetEnumerator();
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| 102 | enumerators[cur].MoveNext();
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| 103 | cur--;
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| 104 | }
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| 105 | return cur < 0;
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| 106 | }
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| 107 |
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| 108 | private static void GetCurrentCombination(List<IEnumerator<double>> enumerators, List<List<double>> allCombinations) {
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| 109 | for (int i = 0; i < enumerators.Count(); i++) {
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| 110 | allCombinations[i].Add(enumerators[i].Current);
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| 111 | }
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| 112 | }
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| 113 | }
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| 114 | }
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