[11656] | 1 | #region License Information
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| 2 | /* HeuristicLab
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[12018] | 3 | * Copyright (C) 2002-2015 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
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[11838] | 4 | * and the BEACON Center for the Study of Evolution in Action.
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[11656] | 5 | *
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| 6 | * This file is part of HeuristicLab.
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| 7 | *
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| 8 | * HeuristicLab is free software: you can redistribute it and/or modify
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| 9 | * it under the terms of the GNU General Public License as published by
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| 10 | * the Free Software Foundation, either version 3 of the License, or
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| 11 | * (at your option) any later version.
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| 12 | *
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| 13 | * HeuristicLab is distributed in the hope that it will be useful,
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| 14 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
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| 15 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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| 16 | * GNU General Public License for more details.
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| 17 | *
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| 18 | * You should have received a copy of the GNU General Public License
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| 19 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
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| 20 | */
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| 21 | #endregion
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| 22 |
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| 23 | using System;
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| 24 | using System.Collections.Generic;
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| 25 | using System.Linq;
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[11662] | 26 | using HeuristicLab.Common;
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[11656] | 27 | using HeuristicLab.Core;
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[12018] | 28 | using HeuristicLab.Encodings.BinaryVectorEncoding;
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[11939] | 29 | using HeuristicLab.Random;
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[11656] | 30 |
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| 31 | namespace HeuristicLab.Algorithms.ParameterlessPopulationPyramid {
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[11838] | 32 | // This code is based off the publication
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| 33 | // B. W. Goldman and W. F. Punch, "Parameter-less Population Pyramid," GECCO, pp. 785–792, 2014
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| 34 | // and the original source code in C++11 available from: https://github.com/brianwgoldman/Parameter-less_Population_Pyramid
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[11656] | 35 | public class LinkageTree {
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[11662] | 36 | private readonly int[][][] occurances;
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| 37 | private readonly List<int>[] clusters;
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[11663] | 38 | private List<int> clusterOrdering;
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[11662] | 39 | private readonly int length;
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[11663] | 40 | private readonly IRandom rand;
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| 41 | private bool rebuildRequired = false;
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[11656] | 42 |
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[11663] | 43 | public LinkageTree(int length, IRandom rand) {
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[11662] | 44 | this.length = length;
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[11663] | 45 | this.rand = rand;
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[11662] | 46 | occurances = new int[length][][];
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[11656] | 47 |
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[11663] | 48 | // Create a lower triangular matrix without the diagonal
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[11662] | 49 | for (int i = 1; i < length; i++) {
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[11656] | 50 | occurances[i] = new int[i][];
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| 51 | for (int j = 0; j < i; j++) {
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| 52 | occurances[i][j] = new int[4];
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| 53 | }
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| 54 | }
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[11662] | 55 | clusters = new List<int>[2 * length - 1];
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[11656] | 56 | for (int i = 0; i < clusters.Length; i++) {
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| 57 | clusters[i] = new List<int>();
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| 58 | }
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[11662] | 59 | clusterOrdering = new List<int>();
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[11656] | 60 |
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| 61 | // first "length" clusters just contain a single gene
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[11662] | 62 | for (int i = 0; i < length; i++) {
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[11656] | 63 | clusters[i].Add(i);
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| 64 | }
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| 65 | }
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| 66 |
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[12018] | 67 | public void Add(BinaryVector solution) {
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[11662] | 68 | if (solution.Length != length) throw new ArgumentException("The individual has not the correct length.");
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[11656] | 69 | for (int i = 1; i < solution.Length; i++) {
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| 70 | for (int j = 0; j < i; j++) {
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| 71 | // Updates the entry of the 4 long array based on the two bits
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[11674] | 72 |
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| 73 | var pattern = (Convert.ToByte(solution[j]) << 1) + Convert.ToByte(solution[i]);
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[11656] | 74 | occurances[i][j][pattern]++;
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| 75 | }
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| 76 | }
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[11663] | 77 | rebuildRequired = true;
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[11656] | 78 | }
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| 79 |
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| 80 | // While "total" always has an integer value, it is a double to reduce
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| 81 | // how often type casts are needed to prevent integer divison
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[11672] | 82 | // In the GECCO paper, calculates Equation 2
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[11656] | 83 | private static double NegativeEntropy(int[] counts, double total) {
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| 84 | double sum = 0;
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[11674] | 85 | for (int i = 0; i < counts.Length; i++) {
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| 86 | if (counts[i] != 0) {
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| 87 | sum += ((counts[i] / total) * Math.Log(counts[i] / total));
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| 88 | }
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[11656] | 89 | }
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| 90 | return sum;
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| 91 | }
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[11662] | 92 |
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[11672] | 93 | // Uses the frequency table to calcuate the entropy distance between two indices.
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| 94 | // In the GECCO paper, calculates Equation 1
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[11674] | 95 | private int[] bits = new int[4];
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[11656] | 96 | private double EntropyDistance(int i, int j) {
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[11663] | 97 | // This ensures you are using the lower triangular part of "occurances"
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[11656] | 98 | if (i < j) {
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| 99 | int temp = i;
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| 100 | i = j;
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| 101 | j = temp;
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| 102 | }
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| 103 | var entry = occurances[i][j];
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| 104 | // extracts the occurrences of the individual bits
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| 105 | bits[0] = entry[0] + entry[2]; // i zero
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| 106 | bits[1] = entry[1] + entry[3]; // i one
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| 107 | bits[2] = entry[0] + entry[1]; // j zero
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| 108 | bits[3] = entry[2] + entry[3]; // j one
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| 109 | double total = bits[0] + bits[1];
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| 110 | // entropy of the two bits on their own
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| 111 | double separate = NegativeEntropy(bits, total);
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| 112 | // entropy of the two bits as a single unit
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| 113 | double together = NegativeEntropy(entry, total);
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| 114 | // If together there is 0 entropy, the distance is zero
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[11662] | 115 | if (together.IsAlmost(0)) {
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| 116 | return 0.0;
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[11656] | 117 | }
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[11662] | 118 | return 2 - (separate / together);
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[11656] | 119 | }
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| 120 |
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[11674] | 121 |
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| 122 |
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[11672] | 123 | // Performs O(N^2) clustering based on the method described in:
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| 124 | // "Optimal implementations of UPGMA and other common clustering algorithms"
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| 125 | // by I. Gronau and S. Moran
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| 126 | // In the GECCO paper, Figure 2 is a simplified version of this algorithm.
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[11674] | 127 | private double[][] distances;
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[11663] | 128 | private void Rebuild() {
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[11674] | 129 | if (distances == null) {
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| 130 | distances = new double[clusters.Length * 2 - 1][];
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| 131 | for (int i = 0; i < distances.Length; i++)
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| 132 | distances[i] = new double[clusters.Length * 2 - 1];
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| 133 | }
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| 134 |
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| 135 |
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[11656] | 136 | // Keep track of which clusters have not been merged
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[11674] | 137 | var topLevel = new List<int>(length);
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| 138 | for (int i = 0; i < length; i++)
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| 139 | topLevel.Add(i);
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[11656] | 140 |
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[11674] | 141 | bool[] useful = new bool[clusters.Length];
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| 142 | for (int i = 0; i < useful.Length; i++)
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| 143 | useful[i] = true;
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| 144 |
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[11656] | 145 | // Store the distances between all clusters
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[11662] | 146 | for (int i = 1; i < length; i++) {
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[11656] | 147 | for (int j = 0; j < i; j++) {
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[11674] | 148 | distances[i][j] = EntropyDistance(clusters[i][0], clusters[j][0]);
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[11656] | 149 | // make it symmetric
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[11674] | 150 | distances[j][i] = distances[i][j];
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[11656] | 151 | }
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| 152 | }
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| 153 | // Each iteration we add some amount to the path, and remove the last
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| 154 | // two elements. This keeps track of how much of usable is in the path.
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| 155 | int end_of_path = 0;
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| 156 |
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| 157 | // build all clusters of size greater than 1
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[11662] | 158 | for (int index = length; index < clusters.Length; index++) {
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[11656] | 159 | // Shuffle everything not yet in the path
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[11674] | 160 | topLevel.ShuffleInPlace(rand, end_of_path, topLevel.Count - 1);
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[11656] | 161 |
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| 162 | // if nothing in the path, just add a random usable node
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| 163 | if (end_of_path == 0) {
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| 164 | end_of_path = 1;
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| 165 | }
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| 166 | while (end_of_path < topLevel.Count) {
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| 167 | // last node in the path
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| 168 | int final = topLevel[end_of_path - 1];
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| 169 |
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| 170 | // best_index stores the location of the best thing in the top level
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| 171 | int best_index = end_of_path;
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[11674] | 172 | double min_dist = distances[final][topLevel[best_index]];
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[11656] | 173 | // check all options which might be closer to "final" than "topLevel[best_index]"
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| 174 | for (int option = end_of_path + 1; option < topLevel.Count; option++) {
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[11674] | 175 | if (distances[final][topLevel[option]] < min_dist) {
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| 176 | min_dist = distances[final][topLevel[option]];
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[11656] | 177 | best_index = option;
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| 178 | }
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| 179 | }
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| 180 | // If the current last two in the path are minimally distant
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[11674] | 181 | if (end_of_path > 1 && min_dist >= distances[final][topLevel[end_of_path - 2]]) {
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[11656] | 182 | break;
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| 183 | }
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| 184 |
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| 185 | // move the best to the end of the path
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| 186 | topLevel.Swap(end_of_path, best_index);
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| 187 | end_of_path++;
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| 188 | }
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| 189 | // Last two elements in the path are the clusters to join
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| 190 | int first = topLevel[end_of_path - 2];
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| 191 | int second = topLevel[end_of_path - 1];
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| 192 |
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| 193 | // Only keep a cluster if the distance between the joining clusters is > zero
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[11674] | 194 | bool keep = !distances[first][second].IsAlmost(0.0);
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[11656] | 195 | useful[first] = keep;
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| 196 | useful[second] = keep;
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| 197 |
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| 198 | // create the new cluster
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| 199 | clusters[index] = clusters[first].Concat(clusters[second]).ToList();
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| 200 | // Calculate distances from all clusters to the newly created cluster
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| 201 | int i = 0;
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| 202 | int end = topLevel.Count - 1;
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| 203 | while (i <= end) {
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| 204 | int x = topLevel[i];
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| 205 | // Moves 'first' and 'second' to after "end" in topLevel
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| 206 | if (x == first || x == second) {
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| 207 | topLevel.Swap(i, end);
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| 208 | end--;
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| 209 | continue;
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| 210 | }
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| 211 | // Use the previous distances to calculate the joined distance
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[11674] | 212 | double first_distance = distances[first][x];
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[11656] | 213 | first_distance *= clusters[first].Count;
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[11674] | 214 | double second_distance = distances[second][x];
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[11656] | 215 | second_distance *= clusters[second].Count;
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[11674] | 216 | distances[x][index] = ((first_distance + second_distance)
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[11656] | 217 | / (clusters[first].Count + clusters[second].Count));
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| 218 | // make it symmetric
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[11674] | 219 | distances[index][x] = distances[x][index];
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[11656] | 220 | i++;
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| 221 | }
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| 222 |
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| 223 | // Remove first and second from the path
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| 224 | end_of_path -= 2;
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| 225 | topLevel.RemoveAt(topLevel.Count - 1);
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| 226 | topLevel[topLevel.Count - 1] = index;
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| 227 | }
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| 228 | // Extract the useful clusters
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[11662] | 229 | clusterOrdering.Clear();
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[11656] | 230 | // Add all useful clusters. The last one is never useful.
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| 231 | for (int i = 0; i < useful.Length - 1; i++) {
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[11662] | 232 | if (useful[i]) clusterOrdering.Add(i);
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[11656] | 233 | }
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[11663] | 234 |
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| 235 | // Shuffle before sort to ensure ties are broken randomly
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[11662] | 236 | clusterOrdering.ShuffleInPlace(rand);
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[11663] | 237 | clusterOrdering = clusterOrdering.OrderBy(i => clusters[i].Count).ToList();
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[11656] | 238 | }
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| 239 |
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[11663] | 240 | public IEnumerable<List<int>> Clusters {
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| 241 | get {
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| 242 | // Just in time rebuilding
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| 243 | if (rebuildRequired) Rebuild();
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| 244 | foreach (var index in clusterOrdering) {
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| 245 | // Send out the clusters in the desired order
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| 246 | yield return clusters[index];
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| 247 | }
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| 248 | }
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[11656] | 249 | }
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| 250 | }
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[11663] | 251 | } |
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