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source: branches/2898_GeneralizedAdditiveModels/HeuristicLab.Clients.Hive/3.3/Util/PersistenceUtil.cs @ 16752

Last change on this file since 16752 was 15583, checked in by swagner, 7 years ago

#2640: Updated year of copyrights in license headers

File size: 1.9 KB
Line 
1#region License Information
2/* HeuristicLab
3 * Copyright (C) 2002-2018 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
4 *
5 * This file is part of HeuristicLab.
6 *
7 * HeuristicLab is free software: you can redistribute it and/or modify
8 * it under the terms of the GNU General Public License as published by
9 * the Free Software Foundation, either version 3 of the License, or
10 * (at your option) any later version.
11 *
12 * HeuristicLab is distributed in the hope that it will be useful,
13 * but WITHOUT ANY WARRANTY; without even the implied warranty of
14 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
15 * GNU General Public License for more details.
16 *
17 * You should have received a copy of the GNU General Public License
18 * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
19 */
20#endregion
21
22using System;
23using System.Collections.Generic;
24using System.IO;
25using HeuristicLab.Persistence.Core;
26using HeuristicLab.Persistence.Default.Xml;
27
28namespace HeuristicLab.Clients.Hive {
29  public static class PersistenceUtil {
30    public static byte[] Serialize(object obj, out IEnumerable<Type> types) {
31      using (MemoryStream memStream = new MemoryStream()) {
32        XmlGenerator.Serialize(obj, memStream, ConfigurationService.Instance.GetConfiguration(new XmlFormat()), false, out types);
33        byte[] jobByteArray = memStream.ToArray();
34        return jobByteArray;
35      }
36    }
37
38    public static byte[] Serialize(object obj) {
39      using (MemoryStream memStream = new MemoryStream()) {
40        XmlGenerator.Serialize(obj, memStream);
41        byte[] jobByteArray = memStream.ToArray();
42        return jobByteArray;
43      }
44    }
45
46    public static T Deserialize<T>(byte[] sjob) {
47      using (MemoryStream memStream = new MemoryStream(sjob)) {
48        T job = XmlParser.Deserialize<T>(memStream);
49        return job;
50      }
51    }
52  }
53}
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