[6976] | 1 | #region License Information
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| 2 | /* HeuristicLab
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[16057] | 3 | * Copyright (C) 2002-2018 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
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[6976] | 4 | *
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| 5 | * This file is part of HeuristicLab.
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| 6 | *
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| 7 | * HeuristicLab is free software: you can redistribute it and/or modify
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| 8 | * it under the terms of the GNU General Public License as published by
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| 9 | * the Free Software Foundation, either version 3 of the License, or
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| 10 | * (at your option) any later version.
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| 11 | *
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| 12 | * HeuristicLab is distributed in the hope that it will be useful,
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| 13 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
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| 14 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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| 15 | * GNU General Public License for more details.
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| 16 | *
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| 17 | * You should have received a copy of the GNU General Public License
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| 18 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
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| 19 | */
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| 20 | #endregion
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| 21 |
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| 22 | using System;
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| 23 | using System.Collections.Generic;
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| 24 | using System.IO;
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| 25 | using HeuristicLab.Persistence.Core;
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| 26 | using HeuristicLab.Persistence.Default.Xml;
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| 27 |
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| 28 | namespace HeuristicLab.Clients.Hive {
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| 29 | public static class PersistenceUtil {
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| 30 | public static byte[] Serialize(object obj, out IEnumerable<Type> types) {
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[7142] | 31 | using (MemoryStream memStream = new MemoryStream()) {
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| 32 | XmlGenerator.Serialize(obj, memStream, ConfigurationService.Instance.GetConfiguration(new XmlFormat()), false, out types);
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| 33 | byte[] jobByteArray = memStream.ToArray();
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| 34 | return jobByteArray;
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| 35 | }
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[6976] | 36 | }
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| 37 |
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| 38 | public static byte[] Serialize(object obj) {
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[7142] | 39 | using (MemoryStream memStream = new MemoryStream()) {
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| 40 | XmlGenerator.Serialize(obj, memStream);
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| 41 | byte[] jobByteArray = memStream.ToArray();
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| 42 | return jobByteArray;
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| 43 | }
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[6976] | 44 | }
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| 45 |
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| 46 | public static T Deserialize<T>(byte[] sjob) {
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[7142] | 47 | using (MemoryStream memStream = new MemoryStream(sjob)) {
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| 48 | T job = XmlParser.Deserialize<T>(memStream);
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| 49 | return job;
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| 50 | }
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[6976] | 51 | }
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| 52 | }
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| 53 | }
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