1 | #region License Information
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2 | /* HeuristicLab
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3 | * Copyright (C) 2002-2016 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
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4 | *
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5 | * This file is part of HeuristicLab.
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6 | *
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7 | * HeuristicLab is free software: you can redistribute it and/or modify
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8 | * it under the terms of the GNU General Public License as published by
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9 | * the Free Software Foundation, either version 3 of the License, or
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10 | * (at your option) any later version.
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11 | *
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12 | * HeuristicLab is distributed in the hope that it will be useful,
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13 | * but WITHOUT ANY WARRANTY; without even the implied warranty of
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14 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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15 | * GNU General Public License for more details.
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16 | *
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17 | * You should have received a copy of the GNU General Public License
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18 | * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
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19 | */
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20 | #endregion
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21 |
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22 | using System;
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23 | using System.Collections.Generic;
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24 | using System.Linq;
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25 | using HeuristicLab.Core;
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26 |
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27 | namespace HeuristicLab.Random {
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28 | public static class RandomEnumerable {
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29 | public static IEnumerable<int> SampleRandomNumbers(int maxElement, int count) {
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30 | return SampleRandomNumbers(Environment.TickCount, 0, maxElement, count);
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31 | }
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32 |
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33 | public static IEnumerable<int> SampleRandomNumbers(int start, int end, int count) {
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34 | return SampleRandomNumbers(Environment.TickCount, start, end, count);
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35 | }
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36 |
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37 | //algorithm taken from progamming pearls page 127
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38 | //IMPORTANT because IEnumerables with yield are used the seed must be specified to return always
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39 | //the same sequence of numbers without caching the values.
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40 | public static IEnumerable<int> SampleRandomNumbers(int seed, int start, int end, int count) {
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41 | int remaining = end - start;
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42 | var mt = new FastRandom(seed);
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43 | for (int i = start; i < end && count > 0; i++) {
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44 | double probability = mt.NextDouble();
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45 | if (probability < ((double)count) / remaining) {
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46 | count--;
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47 | yield return i;
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48 | }
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49 | remaining--;
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50 | }
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51 | }
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52 |
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53 | /// <summary>
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54 | /// Chooses one elements from a sequence giving each element an equal chance.
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55 | /// </summary>
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56 | /// <remarks>
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57 | /// Runtime complexity is O(1) for sequences that are of type <see cref="IList{T}"/> and
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58 | /// O(N) for all other.
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59 | /// </remarks>
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60 | /// <exception cref="ArgumentException">If the sequence is empty.</exception>
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61 | /// <typeparam name="T">The type of the items to be selected.</typeparam>
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62 | /// <param name="source">The sequence of elements.</param>
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63 | /// <param name="random">The random number generator to use, its NextDouble() method must produce values in the range [0;1)</param>
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64 | /// <param name="count">The number of items to be selected.</param>
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65 | /// <returns>An element that has been chosen randomly from the sequence.</returns>
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66 | public static T SampleRandom<T>(this IEnumerable<T> source, IRandom random) {
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67 | if (!source.Any()) throw new ArgumentException("sequence is empty.", "source");
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68 | return source.SampleRandom(random, 1).First();
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69 | }
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70 |
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71 | /// <summary>
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72 | /// Chooses <paramref name="count"/> elements from a sequence with repetition with equal chances for each element.
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73 | /// </summary>
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74 | /// <remarks>
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75 | /// Runtime complexity is O(count) for sequences that are <see cref="IList{T}"/> and
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76 | /// O(N * count) for all other. No exception is thrown if the sequence is empty.
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77 | ///
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78 | /// The method is online.
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79 | /// </remarks>
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80 | /// <typeparam name="T">The type of the items to be selected.</typeparam>
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81 | /// <param name="source">The sequence of elements.</param>
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82 | /// <param name="random">The random number generator to use, its NextDouble() method must produce values in the range [0;1)</param>
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83 | /// <param name="count">The number of items to be selected.</param>
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84 | /// <returns>A sequence of elements that have been chosen randomly.</returns>
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85 | public static IEnumerable<T> SampleRandom<T>(this IEnumerable<T> source, IRandom random, int count) {
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86 | var listSource = source as IList<T>;
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87 | if (listSource != null) {
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88 | while (count > 0) {
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89 | yield return listSource[random.Next(listSource.Count)];
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90 | count--;
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91 | }
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92 | } else {
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93 | while (count > 0) {
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94 | var enumerator = source.GetEnumerator();
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95 | enumerator.MoveNext();
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96 | T selectedItem = enumerator.Current;
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97 | int counter = 1;
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98 | while (enumerator.MoveNext()) {
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99 | counter++;
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100 | if (counter * random.NextDouble() < 1.0)
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101 | selectedItem = enumerator.Current;
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102 | }
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103 | yield return selectedItem;
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104 | count--;
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105 | }
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106 | }
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107 | }
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108 |
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109 | /// <summary>
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110 | /// Chooses <paramref name="count"/> elements from a sequence without repetition with equal chances for each element.
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111 | /// The items are returned in the same order as they appear in the sequence.
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112 | /// </summary>
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113 | /// <remarks>
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114 | /// Runtime complexity is O(N) for all sequences.
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115 | /// No exception is thrown if the sequence contains less items than there are to be selected.
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116 | ///
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117 | /// The method is online.
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118 | /// </remarks>
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119 | /// <typeparam name="T">The type of the items to be selected.</typeparam>
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120 | /// <param name="source">The sequence of elements.</param>
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121 | /// <param name="random">The random number generator to use, its NextDouble() method must produce values in the range [0;1)</param>
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122 | /// <param name="count">The number of items to be selected.</param>
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123 | /// <param name="sourceCount">Optional parameter specifying the number of elements in the source enumerations</param>
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124 | /// <returns>A sequence of elements that have been chosen randomly.</returns>
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125 | public static IEnumerable<T> SampleRandomWithoutRepetition<T>(this IEnumerable<T> source, IRandom random, int count, int sourceCount = -1) {
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126 | if (sourceCount == -1) sourceCount = source.Count();
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127 | int remaining = sourceCount;
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128 | foreach (var item in source) {
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129 | if (random.NextDouble() * remaining < count) {
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130 | count--;
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131 | yield return item;
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132 | if (count <= 0) break;
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133 | }
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134 | remaining--;
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135 | }
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136 | }
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137 |
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138 | /// <summary>
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139 | /// Chooses elements out of a sequence with repetition. The chance that an item is selected is proportional or inverse-proportional
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140 | /// to the <paramref name="weights"/>.
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141 | /// </summary>
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142 | /// <remarks>
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143 | /// In case both <paramref name="inverseProportional"/> and <paramref name="windowing"/> are false values must be > 0,
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144 | /// otherwise an InvalidOperationException is thrown.
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145 | ///
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146 | /// The method internally holds two arrays: One that is the sequence itself and another one for the values.
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147 | /// </remarks>
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148 | /// <typeparam name="T">The type of the items to be selected.</typeparam>
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149 | /// <param name="source">The sequence of elements.</param>
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150 | /// <param name="random">The random number generator to use, its NextDouble() method must produce values in the range [0;1)</param>
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151 | /// <param name="count">The number of items to be selected.</param>
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152 | /// <param name="weights">The weight values for the items.</param>
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153 | /// <param name="windowing">Whether to scale the proportional values or not.</param>
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154 | /// <param name="inverseProportional">Determines whether to choose proportionally (false) or inverse-proportionally (true).</param>
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155 | /// <returns>A sequence of selected items. The sequence might contain the same item more than once.</returns>
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156 | public static IEnumerable<T> SampleProportional<T>(this IEnumerable<T> source, IRandom random, int count, IEnumerable<double> weights, bool windowing = true, bool inverseProportional = false) {
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157 | return source.SampleProportional(random, weights, windowing, inverseProportional).Take(count);
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158 | }
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159 |
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160 | /// <summary>
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161 | /// Same as <seealso cref="SampleProportional<T>"/>, but chooses an item exactly once.
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162 | /// </summary>
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163 | /// <remarks>
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164 | /// In case both <paramref name="inverseProportional"/> and <paramref name="windowing"/> are false values must be > 0,
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165 | /// otherwise an InvalidOperationException is thrown.
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166 | ///
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167 | /// The method internally holds two arrays: One that is the sequence itself and another one for the values.
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168 | ///
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169 | /// The method does not check if the number of elements in source and weights are the same.
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170 | /// </remarks>
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171 | /// <typeparam name="T">The type of the items to be selected.</typeparam>
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172 | /// <param name="source">The sequence of elements.</param>
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173 | /// <param name="random">The random number generator to use, its NextDouble() method must produce values in the range [0;1)</param>
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174 | /// <param name="count">The number of items to be selected.</param>
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175 | /// <param name="weights">The weight values for the items.</param>
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176 | /// <param name="windowing">Whether to scale the proportional values or not.</param>
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177 | /// <param name="inverseProportional">Determines whether to choose proportionally (true) or inverse-proportionally (false).</param>
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178 | /// <returns>A sequence of selected items. Might actually be shorter than <paramref name="count"/> elements if source has less than <paramref name="count"/> elements.</returns>
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179 | public static IEnumerable<T> SampleProportionalWithoutRepetition<T>(this IEnumerable<T> source, IRandom random, int count, IEnumerable<double> weights, bool windowing = true, bool inverseProportional = false) {
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180 | return source.SampleProportionalWithoutRepetition(random, weights, windowing, inverseProportional).Take(count);
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181 | }
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182 | #region Proportional Helpers
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183 | private static IEnumerable<T> SampleProportional<T>(this IEnumerable<T> source, IRandom random, IEnumerable<double> weights, bool windowing, bool inverseProportional) {
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184 | var sourceArray = source.ToArray();
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185 | var valueArray = PrepareProportional(weights, windowing, inverseProportional);
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186 | double total = valueArray.Sum();
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187 |
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188 | while (true) {
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189 | int index = 0;
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190 | double ball = valueArray[index], sum = random.NextDouble() * total;
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191 | while (ball < sum)
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192 | ball += valueArray[++index];
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193 | yield return sourceArray[index];
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194 | }
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195 | }
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196 | private static IEnumerable<T> SampleProportionalWithoutRepetition<T>(this IEnumerable<T> source, IRandom random, IEnumerable<double> weights, bool windowing, bool inverseProportional) {
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197 | var valueArray = PrepareProportional(weights, windowing, inverseProportional);
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198 | var list = new LinkedList<Tuple<T, double>>(source.Zip(valueArray, Tuple.Create));
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199 | double total = valueArray.Sum();
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200 |
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201 | while (list.Count > 0) {
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202 | var cur = list.First;
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203 | double ball = cur.Value.Item2, sum = random.NextDouble() * total; // assert: sum < total. When there is only one item remaining: sum < ball
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204 | while (ball < sum) {
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205 | cur = cur.Next;
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206 | ball += cur.Value.Item2;
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207 | }
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208 | yield return cur.Value.Item1;
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209 | list.Remove(cur);
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210 | total -= cur.Value.Item2;
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211 | }
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212 | }
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213 |
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214 | public static double[] PrepareProportional(IEnumerable<double> weights, bool windowing, bool inverseProportional) {
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215 | double maxValue = double.MinValue, minValue = double.MaxValue;
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216 | double[] valueArray = weights.ToArray();
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217 |
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218 | for (int i = 0; i < valueArray.Length; i++) {
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219 | if (valueArray[i] > maxValue) maxValue = valueArray[i];
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220 | if (valueArray[i] < minValue) minValue = valueArray[i];
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221 | }
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222 | if (minValue == maxValue) { // all values are equal
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223 | for (int i = 0; i < valueArray.Length; i++) {
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224 | valueArray[i] = 1.0;
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225 | }
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226 | } else {
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227 | if (windowing) {
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228 | if (inverseProportional) InverseProportionalScale(valueArray, maxValue);
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229 | else ProportionalScale(valueArray, minValue);
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230 | } else {
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231 | if (minValue < 0.0) throw new InvalidOperationException("Proportional selection without windowing does not work with values < 0.");
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232 | if (inverseProportional) InverseProportionalScale(valueArray, 2 * maxValue);
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233 | }
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234 | }
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235 | return valueArray;
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236 | }
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237 | private static void ProportionalScale(double[] values, double minValue) {
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238 | for (int i = 0; i < values.Length; i++) {
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239 | values[i] = values[i] - minValue;
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240 | }
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241 | }
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242 | private static void InverseProportionalScale(double[] values, double maxValue) {
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243 | for (int i = 0; i < values.Length; i++) {
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244 | values[i] = maxValue - values[i];
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245 | }
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246 | }
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247 | #endregion
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248 |
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249 | /// <summary>
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250 | /// Shuffles an enumerable and returns a new enumerable according to the Fisher-Yates shuffle.
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251 | /// </summary>
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252 | /// <remarks>
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253 | /// Note that the source enumerable is transformed into an array.
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254 | ///
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255 | /// The implementation is described in http://stackoverflow.com/questions/1287567/c-is-using-random-and-orderby-a-good-shuffle-algorithm.
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256 | /// </remarks>
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257 | /// <typeparam name="T">The type of the items that are to be shuffled.</typeparam>
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258 | /// <param name="source">The enumerable that contains the items.</param>
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259 | /// <param name="random">The random number generator, its Next(n) method must deliver uniformly distributed random numbers in the range [0;n).</param>
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260 | /// <returns>An enumerable with the elements shuffled.</returns>
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261 | public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> source, IRandom random) {
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262 | T[] elements = source.ToArray();
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263 | for (int i = elements.Length - 1; i > 0; i--) {
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264 | // Swap element "i" with a random earlier element (including itself)
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265 | int swapIndex = random.Next(i + 1);
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266 | yield return elements[swapIndex];
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267 | elements[swapIndex] = elements[i];
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268 | // we don't actually perform the swap, we can forget about the
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269 | // swapped element because we already returned it.
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270 | }
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271 | if (elements.Length > 0)
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272 | yield return elements[0];
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273 | }
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274 | }
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275 | }
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276 |
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