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source: branches/2521_ProblemRefactoring/HeuristicLab.Common/3.3/EnumerableExtensions.cs @ 16204

Last change on this file since 16204 was 12012, checked in by ascheibe, 10 years ago

#2212 merged r12008, r12009, r12010 back into trunk

File size: 4.4 KB
Line 
1#region License Information
2/* HeuristicLab
3 * Copyright (C) 2002-2015 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
4 *
5 * This file is part of HeuristicLab.
6 *
7 * HeuristicLab is free software: you can redistribute it and/or modify
8 * it under the terms of the GNU General Public License as published by
9 * the Free Software Foundation, either version 3 of the License, or
10 * (at your option) any later version.
11 *
12 * HeuristicLab is distributed in the hope that it will be useful,
13 * but WITHOUT ANY WARRANTY; without even the implied warranty of
14 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
15 * GNU General Public License for more details.
16 *
17 * You should have received a copy of the GNU General Public License
18 * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
19 */
20#endregion
21
22using System;
23using System.Collections.Generic;
24using System.Linq;
25
26namespace HeuristicLab.Common {
27  public static class EnumerableExtensions {
28    /// <summary>
29    /// Selects all elements in the sequence that are maximal with respect to the given value.
30    /// </summary>
31    /// <remarks>
32    /// Runtime complexity of the operation is O(N).
33    /// </remarks>
34    /// <typeparam name="T">The type of the elements.</typeparam>
35    /// <param name="source">The enumeration in which the items with a maximal value should be found.</param>
36    /// <param name="valueSelector">The function that selects the value to compare.</param>
37    /// <returns>All elements in the enumeration where the selected value is the maximum.</returns>
38    public static IEnumerable<T> MaxItems<T>(this IEnumerable<T> source, Func<T, IComparable> valueSelector) {
39      IEnumerator<T> enumerator = source.GetEnumerator();
40      if (!enumerator.MoveNext()) return Enumerable.Empty<T>();
41      IComparable max = valueSelector(enumerator.Current);
42      var result = new List<T>();
43      result.Add(enumerator.Current);
44
45      while (enumerator.MoveNext()) {
46        T item = enumerator.Current;
47        IComparable comparison = valueSelector(item);
48        if (comparison.CompareTo(max) > 0) {
49          result.Clear();
50          result.Add(item);
51          max = comparison;
52        } else if (comparison.CompareTo(max) == 0) {
53          result.Add(item);
54        }
55      }
56      return result;
57    }
58
59    /// <summary>
60    /// Selects all elements in the sequence that are minimal with respect to the given value.
61    /// </summary>
62    /// <remarks>
63    /// Runtime complexity of the operation is O(N).
64    /// </remarks>
65    /// <typeparam name="T">The type of the elements.</typeparam>
66    /// <param name="source">The enumeration in which items with a minimal value should be found.</param>
67    /// <param name="valueSelector">The function that selects the value.</param>
68    /// <returns>All elements in the enumeration where the selected value is the minimum.</returns>
69    public static IEnumerable<T> MinItems<T>(this IEnumerable<T> source, Func<T, IComparable> valueSelector) {
70      IEnumerator<T> enumerator = source.GetEnumerator();
71      if (!enumerator.MoveNext()) return Enumerable.Empty<T>();
72      IComparable min = valueSelector(enumerator.Current);
73      var result = new List<T>();
74      result.Add(enumerator.Current);
75
76      while (enumerator.MoveNext()) {
77        T item = enumerator.Current;
78        IComparable comparison = valueSelector(item);
79        if (comparison.CompareTo(min) < 0) {
80          result.Clear();
81          result.Add(item);
82          min = comparison;
83        } else if (comparison.CompareTo(min) == 0) {
84          result.Add(item);
85        }
86      }
87      return result;
88    }
89
90    /// <summary>
91    /// Compute the n-ary cartesian product of arbitrarily many sequences: http://blogs.msdn.com/b/ericlippert/archive/2010/06/28/computing-a-cartesian-product-with-linq.aspx
92    /// </summary>
93    /// <typeparam name="T">The type of the elements inside each sequence</typeparam>
94    /// <param name="sequences">The collection of sequences</param>
95    /// <returns>An enumerable sequence of all the possible combinations of elements</returns>
96    public static IEnumerable<IEnumerable<T>> CartesianProduct<T>(this IEnumerable<IEnumerable<T>> sequences) {
97      IEnumerable<IEnumerable<T>> result = new[] { Enumerable.Empty<T>() };
98      return sequences.Where(s => s.Any()).Aggregate(result, (current, s) => (from seq in current from item in s select seq.Concat(new[] { item })));
99    }
100  }
101}
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