#region License Information /* HeuristicLab * Copyright (C) 2002-2016 Heuristic and Evolutionary Algorithms Laboratory (HEAL) * * This file is part of HeuristicLab. * * HeuristicLab is free software: you can redistribute it and/or modify * it under the terms of the GNU General Public License as published by * the Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * HeuristicLab is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with HeuristicLab. If not, see . */ #endregion using System; using System.Collections.Generic; using System.Data.Linq; using System.Linq; namespace HeuristicLab.Services.Hive.DataAccess.Daos { public class ResourcePermissionDao : GenericDao { public ResourcePermissionDao(DataContext dataContext) : base(dataContext) { } public override ResourcePermission GetById(Guid id) { throw new NotImplementedException(); } public IEnumerable GetByUserAndGroupIds(IEnumerable userAndGroupIds) { string paramIds = string.Join(",", userAndGroupIds.Select(x => string.Format("'{0}'", x))); if (!string.IsNullOrWhiteSpace(paramIds)) { string query = string.Format(GetGrantedResourcesQuery, paramIds); return DataContext.ExecuteQuery(query); } return Enumerable.Empty(); } #region Compiled queries private static readonly Func> GetByResourceIdQuery = CompiledQuery.Compile((DataContext db, Guid resourceId) => from resourcePermission in db.GetTable() where resourcePermission.ResourceId == resourceId select resourcePermission); #endregion #region String queries private const string GetGrantedResourcesQuery = @" WITH rtree AS ( SELECT ResourceId, ParentResourceId FROM [Resource] UNION ALL SELECT rt.ResourceId, r.ParentResourceId FROM [Resource] r JOIN rtree rt ON rt.ParentResourceId = r.ResourceId AND r.ParentResourceId <> r.ResourceId AND rt.ParentResourceId <> rt.ResourceId ) SELECT DISTINCT rtree.ResourceId FROM rtree, [ResourcePermission] rp WHERE rtree.ParentResourceId = rp.ResourceId AND rp.GrantedUserId IN ({0}) UNION ALL SELECT rp.ResourceId FROM [ResourcePermission] rp WHERE rp.GrantedUserId IN ({0}) ;"; #endregion } }