#region License Information
/* HeuristicLab
* Copyright (C) 2002-2016 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
*
* This file is part of HeuristicLab.
*
* HeuristicLab is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* HeuristicLab is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with HeuristicLab. If not, see .
*/
#endregion
using System;
using System.Collections.Generic;
using System.Data.Linq;
using System.Linq;
namespace HeuristicLab.Services.Hive.DataAccess.Daos {
public class ResourcePermissionDao : GenericDao {
public ResourcePermissionDao(DataContext dataContext) : base(dataContext) { }
public override ResourcePermission GetById(Guid id) {
throw new NotImplementedException();
}
public IEnumerable GetByGrantedUserId(IEnumerable grantedUserId) {
string paramIds = string.Join(",", grantedUserId.Select(x => string.Format("'{0}'", x)));
if (!string.IsNullOrWhiteSpace(paramIds)) {
string query = string.Format(GetGrantedResourcesQuery, paramIds);
return DataContext.ExecuteQuery(query);
}
return Enumerable.Empty();
}
#region Compiled queries
private static readonly Func> GetByResourceIdQuery =
CompiledQuery.Compile((DataContext db, Guid resourceId) =>
from resourcePermission in db.GetTable()
where resourcePermission.ResourceId == resourceId
select resourcePermission);
#endregion
#region String queries
private const string GetGrantedResourcesQuery = @"
WITH rtree AS
(
SELECT ResourceId, ParentResourceId
FROM [Resource]
UNION ALL
SELECT rt.ResourceId, r.ParentResourceId
FROM [Resource] r
JOIN rtree rt ON rt.ParentResourceId = r.ResourceId AND r.ParentResourceId <> r.ResourceId AND rt.ParentResourceId <> rt.ResourceId
)
SELECT DISTINCT rtree.ResourceId
FROM rtree, [ResourcePermission] rp
WHERE rtree.ParentResourceId = rp.ResourceId AND rp.GrantedUserId IN ({0})
UNION ALL
SELECT rp.ResourceId
FROM [ResourcePermission] rp
WHERE rp.GrantedUserId IN ({0})
;";
#endregion
}
}