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source: branches/HiveProjectManagement/HeuristicLab.Services.Hive.DataAccess/3.3/Daos/ResourceDao.cs @ 15503

Last change on this file since 15503 was 15503, checked in by jzenisek, 5 years ago

#2839 added ResourcePermission handling (still in progress)

File size: 4.8 KB
Line 
1#region License Information
2/* HeuristicLab
3 * Copyright (C) 2002-2016 Heuristic and Evolutionary Algorithms Laboratory (HEAL)
4 *
5 * This file is part of HeuristicLab.
6 *
7 * HeuristicLab is free software: you can redistribute it and/or modify
8 * it under the terms of the GNU General Public License as published by
9 * the Free Software Foundation, either version 3 of the License, or
10 * (at your option) any later version.
11 *
12 * HeuristicLab is distributed in the hope that it will be useful,
13 * but WITHOUT ANY WARRANTY; without even the implied warranty of
14 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
15 * GNU General Public License for more details.
16 *
17 * You should have received a copy of the GNU General Public License
18 * along with HeuristicLab. If not, see <http://www.gnu.org/licenses/>.
19 */
20#endregion
21
22using System;
23using System.Collections.Generic;
24using System.Data.Linq;
25using System.Linq;
26
27namespace HeuristicLab.Services.Hive.DataAccess.Daos {
28  public class ResourceDao : GenericDao<Guid, Resource> {
29    public ResourceDao(DataContext dataContext) : base(dataContext) { }
30
31    public override Resource GetById(Guid id) {
32      return GetByIdQuery(DataContext, id);
33    }
34
35    public Resource GetByName(string name) {
36      return GetByNameQuery(DataContext, name);
37    }
38
39    public IQueryable<Resource> GetResourcesWithValidOwner() {
40      return Table.Where(x => x.OwnerUserId != null);
41    }
42
43    public IEnumerable<Resource> GetResourcesByParentId(Guid id) {
44      return DataContext.ExecuteQuery<Resource>(GetResourcesByParentIdQuery, id);
45    }
46
47    public IEnumerable<Guid> GetResourceIdsByParentId(Guid id) {
48      return DataContext.ExecuteQuery<Guid>(GetResourceIdsByParentIdQuery, id);
49    }
50
51    public IEnumerable<Resource> GetResourcesByChildId(Guid id) {
52      return DataContext.ExecuteQuery<Resource>(GetResourcesByChildIdQuery, id);
53    }
54
55    public IEnumerable<Guid> GetResourceIdsByChildId(Guid id) {
56      return DataContext.ExecuteQuery<Guid>(GetResourceIdsByChildIdQuery, id);
57    }
58
59    #region Compiled queries
60    private static readonly Func<DataContext, Guid, Resource> GetByIdQuery =
61      CompiledQuery.Compile((DataContext db, Guid resourceId) =>
62        (from resource in db.GetTable<Resource>()
63         where resource.ResourceId == resourceId
64         select resource).SingleOrDefault());
65
66    private static readonly Func<DataContext, string, Resource> GetByNameQuery =
67     CompiledQuery.Compile((DataContext db, string name) =>
68       (from resource in db.GetTable<Resource>()
69        where resource.Name == name
70        select resource).FirstOrDefault());
71    #endregion
72
73    #region String queries
74    private const string GetResourcesByParentIdQuery = @"
75      WITH rtree AS
76      (
77        SELECT ResourceId, ParentResourceId
78        FROM [Resource]
79        UNION ALL
80        SELECT rt.ResourceId, r.ParentResourceId
81        FROM [Resource] r
82        JOIN rtree rt ON rt.ParentResourceId = r.ResourceId AND r.ParentResourceId <> r.ResourceId AND rt.ParentResourceId <> rt.ResourceId
83      )
84      SELECT DISTINCT res.*
85      FROM rtree, [Resource] res
86      WHERE rtree.ParentResourceId = ({0})
87      AND rtree.ResourceId = res.ResourceId
88    ";
89    private const string GetResourceIdsByParentIdQuery = @"
90      WITH rtree AS
91      (
92        SELECT ResourceId, ParentResourceId
93        FROM [Resource]
94        UNION ALL
95        SELECT rt.ResourceId, r.ParentResourceId
96        FROM [Resource] r
97        JOIN rtree rt ON rt.ParentResourceId = r.ResourceId AND r.ParentResourceId <> r.ResourceId AND rt.ParentResourceId <> rt.ResourceId
98      )
99      SELECT DISTINCT rtree.ResourceId
100      FROM rtree
101      WHERE rtree.ParentResourceId = ({0})
102    ";
103    private const string GetResourcesByChildIdQuery = @"
104      WITH rtree AS
105      (
106        SELECT ResourceId, ParentResourceId
107        FROM [Resource]
108        UNION ALL
109        SELECT rt.ResourceId, r.ParentResourceId
110        FROM [Resource] r
111        JOIN rtree rt ON rt.ParentResourceId = r.ResourceId AND r.ParentResourceId <> r.ResourceId AND rt.ParentResourceId <> rt.ResourceId
112      )
113      SELECT DISTINCT res.*
114      FROM rtree, [Resource] res
115      WHERE rtree.ResourceId = ({0})
116      AND rtree.ParentResourceId = res.ResourceId
117    ";
118    private const string GetResourceIdsByChildIdQuery = @"
119      WITH rtree AS
120      (
121        SELECT ResourceId, ParentResourceId
122        FROM [Resource]
123        UNION ALL
124        SELECT rt.ResourceId, r.ParentResourceId
125        FROM [Resource] r
126        JOIN rtree rt ON rt.ParentResourceId = r.ResourceId AND r.ParentResourceId <> r.ResourceId AND rt.ParentResourceId <> rt.ResourceId
127      )
128      SELECT DISTINCT rtree.ParentResourceId
129      FROM rtree
130      WHERE rtree.ResourceId = ({0})
131    ";
132    #endregion
133  }
134}
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